MCQ
Product of this reaction is


- A

- ✓

- C

- D








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$C{H_3} - CH = C{H_2}\xrightarrow[{CC{l_4}}]{{B{r_2}}}A\xrightarrow[{(3\,\,moles)}]{{\mathop N\limits^ \oplus a\mathop N\limits^\Theta {H_2}}}B\xrightarrow{{C{H_3} - Br}}C\xrightarrow[{{H_2}}]{{Pd + BaS{O_4}}}D$
$N_2H_4 + IO_3^-+ 2H^+ + Cl^- \rightarrow ICl + N_2 + 3H_2O$
The equivalent masses of $N_2H_4$ and $KIO_3$ respectively are :-