MCQ
Product $(Q)$ will be


- A

- ✓

- C

- D








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$(A)$ $P$ can be reduced to a primary alcohol using $NaBH _4$.
$(B)$ Treating $P$ with conc. $NH _4 OH$ solution followed by acidification gives $Q$.
$(C)$ Treating $Q$ with a solution of $NaNO _2$ in aq. $HCl$ liberates $N _2$.
$(D)$ $P$ is more acidic than $CH _3 CH _2 COOH$.
