MCQ
Product $[ X ]$ formed in the above reaction is :
- ✓
- B
- C$H _3 C - CH _2- CH = CH _2$
- D$H _3 C - CH = CH - CH _3$
✓
Answer
Correct option: A.
a
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The formation of $S{O_3}$ takes place according to the following reaction, $2S{O_2} + {O_2}$ $\rightleftharpoons$ $2S{O_3}$; $\Delta H = - 45.2\;k\,cal$ The formation of $S{O_3}$ is favoured by
→Which of the following statement is not correct
An optically active alcohol of formula $C_9H_{12}O_2$ produced the following compound when refluxed with $KMnO_4$
→What is structure of $(A)$ ?
The original compound showed these properties also :
$\mathop {{C_9}{H_{12}}{O_2}}\limits_{(A)} \,\xrightarrow{{Na}}\,{H_2}$ liberated
$\mathop {{C_9}{H_{12}}{O_2}}\limits_{(A)} \,\xrightarrow{{Br}}$ no rapid reaction
$\mathop {{C_9}{H_{12}}{O_2}}\limits_{(A)} \,\xrightarrow[{cool}]{{Cr{O_3}\,/\,{H^ + }}}{C_9}{H_8}{O_3}$
For a cell reaction involving a two-electron change, the standard emf of the cell is found to be $0.295\,V $ at ${25\,^o}C$. The equilibrium constant of the reaction at ${25\,^o}C$ will be
→Dipole moments of given compound will be
Necessary conditions for halogenation are
Relation between $(A)$ and $(B)$ is
→Dipole moment is shown by
When $Br_2$ is treated with aqueous solutions of $NaF,\, NaCl$ and $NaI$ separately
→Consider the given reaction :
→$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}\xrightarrow{{{C_6}{H_5}COOOH}}\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_3}}
\end{array}$
The above reaction is known as :