MCQ
Prof. Sandy Gilbert asked his students to prepare $2-$ chloropropane by different methods
Kaushal's method : $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}\xrightarrow{{KCl}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
Preeti's method : $C{H_3} - CH = C{H_2}\xrightarrow{{C{l_2} + {H_2}O}}$
Raghav's method : $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}\xrightarrow[{Pyridine}]{{SOC{l_2}}}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
- AAll three methods are correct
- ✓Only Raghav's method is correct
- COnly Preeti's method is correct
- DKaushal's and Raghav's method both are correct
