MCQ
Propan$-1-$ol can be prepared from propene by alcohol
- A${H_2}O/{H_2}S{O_4}$
- B$Hg{(OAc)_2}/{H_2}O$ followed by $NaB{H_4}$
- ✓${B_2}{H_6}$ followed by ${H_2}{O_2}$
- D$C{H_3}C{O_2}H/{H_2}S{O_4}$
✓
Answer
Correct option: C.
${B_2}{H_6}$ followed by ${H_2}{O_2}$
c
(c) $6C{{H}_{3}}-CH=C{{H}_{2}}+{{B}_{2}}{{H}_{6}}\xrightarrow{{{H}_{2}}{{O}_{2}}}$
(c) $6C{{H}_{3}}-CH=C{{H}_{2}}+{{B}_{2}}{{H}_{6}}\xrightarrow{{{H}_{2}}{{O}_{2}}}$
$C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH$
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