STD 12 -8.1. Aldehydes and ketones — JEE STD 11 Science — Question

$\begin{array}{*{20}{c}}
  {\,\,\,\,\,C{H_3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} O{\mkern 1mu} } \\ 
  {\,\,\,|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} ||} \\ 
  {C{H_3} - CH - C - OH} 
\end{array}$ $+ C{H_3} - N{H_2} \to 'A'\xrightarrow[\Delta ]{}'B'\xrightarrow{\begin{subarray}{l} 
  {\text{LiAl}}{{\text{H}}_4} \\ 
  {\text{(excess)}} 
\end{subarray} }'C'$ 

The final product $‘C’$ will be

$A$                       ||                        $B$