MCQ
Propene on treatment with  $ HBr $ gives
  • Isopropyl bromide
  • B
    Propyl bromide
  • C
    $1, 2-$ dibromoethane
  • D
    None of the above

Answer

Correct option: A.
Isopropyl bromide
a
(a)$C{H_3} - CH = C{H_2} + HBr\xrightarrow[\substack{ {\text{Marko wnikoff's}} \\ {\text{ rule}} } ]{}C{H_3} - \mathop {\mathop {CH}\limits_{|\,\,\,\,} }\limits_{Br\,}  - C{H_3}$

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