MCQ
Propene when heated with chlorine at about ${500\,^o}C$ forms
  • $C{H_2}Cl.CH = C{H_2}$
  • B
    $C{H_3}.CHCl.C{H_2}Cl$
  • C
    $C{H_2}Cl.CHCl.C{H_2}Cl$
  • D
    All the three

Answer

Correct option: A.
$C{H_2}Cl.CH = C{H_2}$
a
(a) $C{H_3} - CH = C{H_2} + C{l_2}\xrightarrow{{500{\,^o}C}}$ $\begin{array}{*{20}{c}}
  {C{H_2} - CH = C{H_2}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {Cl\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array} + HCl$

This reaction is called allylic halogenation reaction because halogenation occurs at the allylic position of an alkene

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