Question
Prove that: $\frac{1-\cos2\text{x}+\sin2\text{x}}{1+\cos2\text{x}+\sin2\text{x}}=\tan\text{x}$

Answer

$\text{LHS}=\frac{1-\cos2\text{x}+\sin2\text{x}}{1+\cos2\text{x}+\sin2\text{x}}$ $=\frac{2\sin^2\text{x}+2\sin\text{x},\cos\text{x}}{2\cos^2+2\sin\text{x},\cos\text{x}}$ $=\frac{2\sin\text{x}(\sin\text{x}+\cos\text{x})}{2\cos\text{x}(\cos\text{x}+\sin\text{x})}$ $=\frac{\sin\text{x}}{\cos\text{x}}$ $=\tan\text{x}=\text{RHS}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free