Question
Prove that $2(\bar{a}-\bar{b}) \times 2(\bar{a}+\bar{b})=8(\bar{a} \times \bar{b})$
$\ldots[\because \bar{a} \times \bar{a}=\bar{b} \times \bar{b}=\overline{0}$ and $-(\bar{b} \times \bar{a})=\bar{a} \times \bar{b}]$
$=\mathrm{RHS}$
$\therefore 2(\bar{a}-\bar{b}) \times 2(\bar{a}+\bar{b})=8(\bar{a} \times \bar{b})$.
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