Question
Prove that:
$2\sin\frac{5\pi}{12}\cos\frac{\pi}{12}=\frac{\sqrt3+2}{2}$

Answer

$\text{LHS}=2\sin\frac{5\pi}{12}\cos\frac{\pi}{12}$
$\because\ 2\sin\text{A}\sin\text{B}=\sin(\text{A+B})+\sin(\text{A}-\text{B})$
$=\ \Big(\frac{5\pi}{12}+\frac{\pi}{12}\Big)+\sin\Big(\frac{5\pi}{12}-\frac{\pi}{12}\Big)$
$=\ \sin\frac{\pi}{2}+\sin\frac{\pi}{3}$
$=\ 1+\frac{\sqrt3}{2}=\frac{2+\sqrt3}{2}=\text{RHS}(\text{Taking LCM})$

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