Question
Prove that: $2\sin\frac{5\pi}{12}\sin\frac{\pi}{12}=\frac{1}{2}$

Answer

$\text{LHS}=2\sin\frac{5\pi}{12}\sin\frac{\pi}{12}$ $\because\ 2\sin\text{A}\sin\text{B}=\cos(\text{A}-\text{B})-\cos(\text{A+B})$ $\Rightarrow\ 2\sin\frac{5\pi}{12}\sin\frac{\pi}{12}=\cos\Big(\frac{5\pi}{12}-\frac{\pi}{12}\Big)-\cos\Big(\frac{5\pi}{12}+\frac{\pi}{12}\Big)$ $=\ \cos\Big(\frac{4\pi}{12}\Big)-\cos\Big(\frac{6\pi}{12}\Big)$ $=\ \cos\Big(\frac{\pi}{3}\Big)-\cos\Big(\frac{6\pi}{12}\Big)$ $=\ \frac{1}{2}-0=\frac{1}{2}=\text{RHS}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free