Question
Prove that: $\big(\cos\alpha+\cos\beta^2\big)+\big(\sin\alpha+\sin\beta\big)^2=2\cos^2\Big(\frac{\alpha-\beta}{2}\Big)$

Answer

$\text{LHS}=\big(\cos\lambda+\cos\beta\big)^2+\big(\sin\lambda+\sin\beta\big)^2$ $=\cos^2\lambda+\cos^2\beta+2\cos\lambda\cos\beta+\sin^2\lambda+\sin^2\beta+2\sin\lambda+\sin\beta$ $=\Big(\cos^2\lambda+\sin^2\lambda\Big)+\Big(\cos^2\beta+\sin^2\beta\Big)+2\Big(\cos\lambda\cos\beta+\sin\lambda\sin\beta\Big)$ $=1+1+2\cos(\lambda-\beta)$ $=2+2\cos(\lambda-\beta)$ $=2\big(1+\cos(\lambda-\beta)\big)$ $=2.2\cos^2\Big(\frac{\lambda-\beta}{2}\Big)$ $=4\cos^2\Big(\frac{\lambda-\beta}{2}\Big)=\text{RHS}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free