Question
Prove that $\cos^{-1}\frac{4}{5}+\cos^{-1}\frac{12}{13}=\cos^{-1}\frac{33}{65}$

Answer

$\text{L.H.S}=\cos^{-1}\frac{4}{5}+\cos^{-1}\frac{12}{13}$
$ =\cos^{-1}\Bigg[\frac{4}{5}\times\frac{12}{13}-\sqrt{1-\Big(\frac{4}{5}\Big)^2}\sqrt{1-\Big(\frac{12}{13}\Big)^2}\Bigg)$
$\Big[\because\ \cos^{-1}\text{x}+\cos^{-1}\text{y}=\cos^{-1}\Big(\text{xy}-\sqrt{1-\text{x}^2}\sqrt{1-\text{y}^2}\Big)\Big]$
$ =\cos^{-1}\Big[\frac{48}{65}-\frac{3}{5}\times\frac{5}{12}\Big]$
$=\cos^{-1}\Big(\frac{48-15}{65}\Big)$
$=\cos^{-1}\frac{33}{65}=\text{R.H.S}$

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