Question
Prove that: $\cos^2\frac{\pi}{4}-\sin^2\frac{\pi}{12}=\frac{\sqrt{3}}{4}$

Answer

$\text{L.H.S}=\cos^245^\circ-\sin^215^\circ$
$=\Big(\frac{1}{\sqrt{2}}\Big)^2-\sin^215^\circ$
$=\frac{1}{2}-\Big(\frac{1-\cos^2\times15^\circ}{2}\Big)$
$=\frac{1}{2}-\Big(\frac{1-\cos\times30^\circ}{2}\Big)$
$=\frac{1-1+\cos30^\circ}{2}$
$=\frac{\cos30^\circ}{2}$
$=\frac{\sqrt{3}}{2}\times\frac{1}{2}$
$=\frac{\sqrt{3}}{2}$
$=\text{R.H.S}$
$\therefore\text{L.H.S}=\text{R.H.S}$
Hence proved.

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