Question
Prove that: $\cos^2 2x-\cos^2 6x = \sin 4x \sin 8x$

Answer

We have L.H.S$= \cos^2 2x-\cos^2 6x$
[$\because \cos^2B - \cos^2A = \sin (A+B) \sin (A - B)] $
$= \sin 8 x \sin 4x =$ R.H.S.

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