Question
Prove that:
$\cos24^\circ\cos55^\circ+\cos125^\circ+\cos204^\circ+\cos300^\circ=\frac12$

Answer

$\text{L.H.S}=\cos24^\circ+\cos55^\circ+\cos125^\circ+\cos204^\circ+\cos300^\circ$
$=\cos24^\circ+\cos204^\circ+\cos55^\circ+\cos125^\circ+\cos300^\circ$
$=\cos24^\circ+\cos(\pi+24^\circ)+\cos55^\circ+\cos(\pi-55^\circ)+\cos\Big(2\pi-\frac{\pi}{3}\Big)$
$=\cos24^\circ-\cos24^\circ+\cos55^\circ+\cos55^\circ-\cos\frac{\pi}{3}$
$=\cos\frac{\pi}{3}$
$=\frac{1}{2}$
$=\text{R.H.S}$
$\text{Proved}$

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