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Trigonometric Ratios Of Compound Angles — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometric Ratios Of Compound Angles3 Marks
Question
Prove that:
$\cos36^\circ\cos42^\circ\cos60^\circ\cos78^\circ=\frac{1}{16}$
✓

Answer

$\text{LHS}=\cos36^\circ.\cos42^\circ.\cos60^\circ.\cos78^\circ$
$=\frac{1}{2}\cos36^\circ.\cos60^\circ\big(2\cos42^\circ.\cos78^\circ\big)$
$=\frac{1}{2}\bigg(\frac{\sqrt{5}+1}{4}\bigg).\frac{1}{2}(\cos120^\circ+\cos36^\circ)$
$=\frac{\big(\sqrt{5}+1\big)}{16}\Big(\frac{-1}{2}+\frac{\sqrt{5}+1}{4}\Big)$
$=\frac{\sqrt{5}+1}{16}\Big(\frac{-2+\sqrt{5}+1}{4}\Big)$
$=\frac{\big(\sqrt{5}+1\big)\big(\sqrt{5}-1\big)}{64}$
$=\frac{5-1}{64}$
$\frac{1}{16}$
$=\text{RHS}$

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