Question
Prove that:
$\cos570^\circ\sin510^\circ+\sin(-330^\circ)\cos(-390^\circ)=0$

Answer

$\text{L.H.S}=\cos570^\circ\sin510^\circ+\sin(-330^\circ)\cos(-390^\circ)$
$\cos\Big(3\pi+\frac{\pi}{6}\Big)\sin\Big(3\pi-\frac{\pi}{6}\Big)-\sin330^\circ\cos390^\circ$$\begin{pmatrix}\because\sin(-\theta)=-\sin\theta\text{ and}\\\cos(-\theta)=\cos\theta\end{pmatrix}$
$=-\cos\frac{\pi}{6}\sin\frac{\pi}{6}-\sin\Big(2\pi-\frac{\pi}{6}\Big)\cos\Big(2\pi+\frac{\pi}{6}\Big)$
$=-\sin\frac{\pi}{6}\cos\frac{\pi}{6}+\sin\frac{\pi}{6}.\cos\frac{\pi}{6}$ $(\because\sin(2\pi-\theta)=-\sin\theta)$
$= 0$
$\text{= R.H.S}$
$\text{Proved}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free