Question
Prove that:
$\cos\text{x}\cos\frac{\text{x}}{2}-\cos3\text{x}\cos\frac{9\text{x}}{2}=\sin7\text{x}\sin8\text{x}.$
$\cos\text{x}\cos\frac{\text{x}}{2}-\cos3\text{x}\cos\frac{9\text{x}}{2}=\sin7\text{x}\sin8\text{x}.$
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classes
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0-10
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10-20
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20-30
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30-40
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40-50
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50-60
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Frequencies
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6
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8
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14
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16
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4
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2
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$A=\left[\begin{array}{cc}4 & -2 \\ 2 & 3\end{array}\right], B=\left[\begin{array}{cc}-1 & 1 \\ 3 & -2\end{array}\right]$ and $C=\left[\begin{array}{cc}4 & 1 \\ 2 & -1\end{array}\right]$
$\frac{1+7 i }{(2- i )^2}$