Question
Prove that cot x cot2x - cot2x cot3x - cot3x cotx = 1

Answer

We have cot 3x = cot (2x + x)
$ = \frac{{\cot 2x\cot x - 1}}{{\cot 2x + \cot x}}$
$\therefore $ cot 3x (cot 2x + cot x ) = cot 2x.cot x - 1
$ \Rightarrow \cot 3x \cdot \cot 2x$+ cot 3x.cot x = cot 2x.cot x - 1
$ \Rightarrow $ cot 3x cot 2x + cot 3x cot x - cot 2x cot x +1 = 0
$\therefore \cot x\cot 2x - \cot 2x\cot 3x$$ - \cot 3x \cdot \cot x = 1$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free