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Trigonometric Ratios Of Multiple And Sub Multiple Angles — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometric Ratios Of Multiple And Sub Multiple Angles3 Marks
Question
Prove that: $\frac{\cos11^\circ+\sin11^\circ}{\cos11^\circ-\sin11^\circ}=\tan56^\circ$$ $
✓

Answer

$\text{L.H.S}=$ $\frac{\cos11^\circ+\sin11^\circ}{\cos11^\circ-\sin11^\circ}$ dividing num erator and demomintor by $\cos11^\circ$we get,
$\frac{\frac{\cos11^\circ}{\cos11^\circ}+\frac{\sin11^\circ}{\cos11^\circ}}{\frac{\cos11^\circ}{\cos11^\circ}-\frac{\sin11^\circ}{\cos11^\circ}}{}$ $\Big[\because\tan\theta=\frac{\sin\theta}{\cos\theta}\Big]$ $=\frac{1+\tan11^\circ}{1-\tan11^\circ}$ $\big[\tan45^\circ=1\big]$ $=\frac{\tan45^\circ+\tan11^\circ}{1-\tan45^\circ\times\tan11^\circ}$ $\Big[\because\tan\text{(A+B)=}\frac{\tan\text{A}+\tan\text{B}}{1-\tan\text{A}\tan\text{B}}\Big]$ $=\tan(45^\circ+11^\circ)$ $=\tan56^\circ$ $=\text{R.H.S}$ $\text{L.H.S}=\text{R.H.S}$ Hence proved.

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