Question
Prove that: ${\sin ^2}\frac{\pi }{6} + {\cos ^2}\frac{\pi }{3} - {\tan ^2}\frac{\pi }{4} = - \frac{1}{2}$
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Find the middle term in the expansion of:
$\Big(\text{x}^2-\frac{2}{\text{x}}\Big)^{10}$