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Trigonometry — Mathematics STD 10 — Question

ICSE BoardEnglish MediumSTD 10MathematicsTrigonometry2 Marks
Question
Prove that $\sin( 90^\circ - \theta ) \sin \theta \cot \theta = \cos^2\theta .$
✓

Answer

$LHS = \sin( 90^\circ - \theta ) \sin \theta \cot \theta$
$= \cos \theta . \sin \theta $.$\frac{\cos \theta}{\sin \theta}$
$= \cos^2\theta$
$= RHS$
Hence proved.

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