Question
Prove that: $\sin ^2 6 x-\sin ^2 4 x=\sin 2 x \sin 10 x$

Answer

We have L.H.S. $ = {\sin ^2}6x - {\sin ^2}4x$
$ = \sin (6x + 4x) \cdot \sin (6x - 4x)$
$[\because {\sin ^2}A - {\sin ^2}B = \sin (A + B)\sin (A - B)]$
$ = \sin 10x \cdot \sin 2x = R.H.S.$

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