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Transformation Formulae — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsTransformation Formulae2 Marks
Question
Prove that:
$\sin65^\circ+\cos65^\circ=\sqrt2\cos20​​^\circ$
✓

Answer

We have,
$\text{LHS}=\sin 65^\circ+\cos65^\circ$
$=\ \sin(45^\circ+20^\circ)+\cos(90^\circ-25^\circ)$
$=\ \sin(45^\circ+20^\circ)+\sin25^\circ$
$=\ \sin(45^\circ+20^\circ)+\sin(45^\circ-20^\circ)$
$=\ 2\sin45^\circ\cos20^\circ$
$=\ 2\times\frac{1}{\sqrt2}\cos20^\circ$
$=\ \frac{\sqrt2\times\sqrt2}{\sqrt2}\times\cos20^\circ$
$=\ \sqrt2\cos20^\circ$
$=\ \text{RHS}$
$\therefore\ \sin60^\circ+\cos65^\circ=\sqrt2\cos20^\circ\ \text{Hence proved}.$

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