Question
Prove that:
$\frac{\sin\theta}{\cos(90^\circ-\theta)}+\frac{\cos\theta}{\sin(90^\circ-\theta)}=2$
$\frac{\sin\theta}{\cos(90^\circ-\theta)}+\frac{\cos\theta}{\sin(90^\circ-\theta)}=2$
✓
Answer
$\text{L.H.S.}=\frac{\sin\theta}{\cos(90^\circ-\theta)}+\frac{\cos\theta}{\sin(90^\circ-\theta)}$
$=\frac{\sin\theta}{\sin\theta}+\frac{\cos\theta}{\cos\theta}$
$=1+1$
$=2$
$=\text{R.H.S.}$
Hence Proved.
$=\frac{\sin\theta}{\sin\theta}+\frac{\cos\theta}{\cos\theta}$
$=1+1$
$=2$
$=\text{R.H.S.}$
Hence Proved.
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