Question
Prove that the function f given by f(x) = x - [x] is increasing in (0, 1).

Answer

f(x) = x - [x]

Let $\text{x}_1,\text{x}_2\in(0,1)$ such that x1 < x2. Then

[x1] = [x2] = 0 ....(1)

Now,

x1 < x2

⇒ x1 - [x1] < x2 - [x2] [From eq. (1)]

⇒ f(x1) < f(x2)

$\therefore$ x1 < x2

$\Rightarrow\text{f}(\text{x}_1)<\text{f}(\text{x}_2),\forall\ \text{x}_1,\text{x}_2\in(0,1)$

Hence, f(x) is increasing on (0, 1).

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions