Question
Prove that the function f given by f(x) = x - [x] is increasing in (0, 1).
Let
$\text{x}_1,\text{x}_2\in(0,1)$ such that x1 < x2. Then[x1] = [x2] = 0 ....(1)
Now,
x1 < x2
⇒ x1 - [x1] < x2 - [x2] [From eq. (1)]
⇒ f(x1) < f(x2)
$\therefore$ x1 < x2
$\Rightarrow\text{f}(\text{x}_1)<\text{f}(\text{x}_2),\forall\ \text{x}_1,\text{x}_2\in(0,1)$
Hence, f(x) is increasing on (0, 1).
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$\begin{bmatrix}\cos\theta & \sin\theta \\-\sin\theta & \cos\theta \end{bmatrix}$