Question
Prove that the function given by f(x) = cos x is increasing in ($\pi$, 2$\pi$)

Answer

Note that f ′(x) = – sin x
Since for each x $\in$ ($\pi$, 2$\pi$), sin x < 0,
we have f ′(x) > 0
Therefore, f is increasing in ($\pi$, 2$\pi$).

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