Question
Prove that the line segment joining the midpoints of two sides of a triangle is parallel to and half of the third side.

Answer

Let the triangle be $ABC$. If $M$ and $N$ are the midpoints of $AB$ and $AC$ respectively, then $\overrightarrow{ AM }=1 / 2 \overrightarrow{ AB }$ and $\overrightarrow{ AN }=1 / 2 \overrightarrow{ AC }$.
Thus by triangle law $ \overrightarrow{ AN }=\overrightarrow{ AM }+\overrightarrow{ MN }$
$\therefore \overline{ MN }=\overrightarrow{ AN }-\overline{ AM }=\frac{\overrightarrow{ AC }-\overline{ AB }}{2}=\frac{\overrightarrow{ BC }}{2} $
Thus, $\overrightarrow{ MN }$ is parallel to and half as long as $\overline{ BC }$.
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