Question
Prove that:
$
\sin ^2 \frac{\pi}{18}+\sin ^2 \frac{\pi}{9}+\sin ^2 \frac{7 \pi}{18}+\sin ^2 \frac{4 \pi}{9}=2
$
$
\sin ^2 \frac{\pi}{18}+\sin ^2 \frac{\pi}{9}+\sin ^2 \frac{7 \pi}{18}+\sin ^2 \frac{4 \pi}{9}=2
$
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