Question
Prove that:
sin4 θ – cos4 θ = 1 – 2cos2 θ

Answer

L.H.S = sin4θ – cos4θ
= (sin2θ – cos2θ)(sin2θ + cos2θ)
= (sin2θ – cos2θ)
= (1 – cos2θ – cos2θ)
= 1- 2cos2θ

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