Question
 Prove the following:
$\cot4\text{x}(\sin5\text{x}+\sin3\text{x})=\cot4\text{x}(\sin5\text{x}-\sin3\text{x})$

Answer

$\text{L.H.S.}=\cot4\text{x}(\sin5\text{x}+\sin3\text{x})$

$=\frac{\cos4\text{x}}{\sin4\text{x}}[2\sin4\text{x}\cos\text{x}]$

$=2\cos4\text{x}\cos\text{x}$

$\text{R.H.S.}=\cot4\text{x}(\sin5\text{x}-\sin3\text{x})$

$\text{L.H.S.} = \text{R.H.S.}$

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