Question
Prove the following : $\sin 40^{\circ}-\cos 70^{\circ}=\sqrt{3} \cos 80^{\circ}$
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$\sqrt[3]{126}$
f = {(1, 3), (2, 4), (3, 5), (4, 6)}
g = {(3, 6), (4, 8), (5, 10), (6, 12)}
$\left[\begin{array}{ccc}5 & 0 & 5 \\ 1 & 99 & 100 \\ 6 & 99 & 105\end{array}\right]$