Question
Prove the following trigonometric identities.
$\tan^2\theta-\sin^2\theta=\tan^2\theta\sin^2\theta$

Answer

$\text{L.H.S}=\tan^2\theta-\sin^2\theta$
$=\frac{\sin^2\theta}{\cos^2\theta}-\frac{\sin^2\theta}{1}$
$=\sin^2\theta\Big[\frac{1}{\cos^2\theta}-\frac{1}{1}\Big]$
$=\sin^2\theta\Big(\frac{1-\cos^2\theta}{\cos^2\theta}\Big)=\sin^2\theta\cdot\frac{\sin^2\theta}{\cos^2\theta}$
$\sin^2\theta\cdot\tan^2\theta=\text{R.H.S}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free