Question
Prove the given identity, where the angles involved are acute angles for which the expressions are defined. $\frac { \cos A } { 1 + \sin A } + \frac { 1 + \sin A } { \cos A } = 2 \sec A$

Answer

$L H S = \frac { \cos A } { 1 + \sin A } + \frac { 1 + \sin A } { \cos A }$
$= \frac { \cos ^ { 2 } A + ( 1 + \sin A ) ^ { 2 } } { ( 1 + \sin A ) \cos A } = \frac { \cos ^ { 2 } A + 1 + \sin ^ { 2 } A + 2 \sin A } { ( 1 + \sin A ) \cos A }$
$= \frac { 1 + 1 + 2 \sin A } { ( 1 + \sin A ) \cos A } \because \sin ^ { 2 } A + \cos ^ { 2 } A = 1$
$= \frac { 2 + 2 \sin A } { ( 1 + \sin A ) \cos A } = \frac { 2 ( 1 + \sin A ) } { ( 1 + \sin A ) \cos A }$
$= \frac { 2 } { \cos A } = 2 \cdot \frac { 1 } { \cos A } = 2 \sec A = R H S$

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