Question
Prove.
$(\cot A-\operatorname{cosec} A)^2=\frac{1-\cos A}{1+\cos A}$

Answer

$\text { R.H.S }=\frac{1-\cos A}{1+\cos A}$
$ =\frac{(1-\cos A)(1-\cos A)}{(1+\cos A)(1-\cos A)}$
v =\frac{(1-\cos A)^2}{1-\cos ^2 A} $
$=\frac{(1-\cos A)^2}{\sin ^2 A} $
$ =\left(\frac{1}{\sin A}-\frac{\cos A}{\sin A}\right)^2$
$=(\operatorname{cosec} A-\cot A)^2$
$=(\cot A-\operatorname{cosec} A)^2 $
$ =\text { L.H.S }$

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