Question
Prove.$\sin ^4 A-\cos ^4 A=2 \sin ^2 A-1$

Answer

$\text { LHS }=\sin ^4 A-\cos ^4 A$
$=\left(\sin ^2 A\right)^2-\left(\cos ^2 A\right)^2$
$=\left(\sin ^2 A+\cos ^2 A\right)\left(\sin ^2 A-\cos ^2 A\right)$
$=\sin ^2 A-\cos ^2 A$
$=\sin ^2 A-\left(1-\sin ^2 A\right)$
$=2 \sin ^2 A-1 \text { RHS }$

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