Question
Prove.
$\sqrt{\frac{1+\sin A}{1-\sin A}}=\sec A+\tan A$
$\sqrt{\frac{1+\sin A}{1-\sin A}}=\sec A+\tan A$
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(i) (-6, 4)
(ii) (0, 5)
(iii) (3, -4)
The locus of points inside a circle and equidistant from two fixed points on the circumference of the circle.