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STD 12 - 4. d and f- block elements — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - 4. d and f- block elements4 Marks
MCQ
Prussian blue is due to the formation of
  • ✓
    $F{e_4}{\left[ {Fe{{(CN)}_6}} \right]_3}$
  • B
    $F{e_2}\left[ {Fe{{(CN)}_6}} \right]$
  • C
    $F{e_3}\left[ {Fe{{(CN)}_6}} \right]$
  • D
    $Fe{\left[ {Fe{{(CN)}_6}} \right]_3}$
✓

Answer

Correct option: A.
$F{e_4}{\left[ {Fe{{(CN)}_6}} \right]_3}$
a
It’s Obvious.
 

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