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8.3. Organic chemistry purification and characterization — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry8.3. Organic chemistry purification and characterization1 Mark
MCQ
Prussian blue is formed when
  • A
    Ferrous sulphate reacts with $FeC{l_3}$
  • ✓
    Ferric sulphate reacts with ${K_4}\left[ {Fe{{(CN)}_6}} \right]$
  • C
    Ferrous ammonium sulphate reacts with $FeC{l_3}$
  • D
    Ammonium sulphate reacts with $FeC{l_3}$
✓

Answer

Correct option: B.
Ferric sulphate reacts with ${K_4}\left[ {Fe{{(CN)}_6}} \right]$
b
(b) $F{e_2}\,{(S{O_4})_3} \to 2F{e^{3 + }} + 3SO_4^{2 - }$
${K_4}[Fe{(CN)_6}] + 2F{e^{3 + }} \to \mathop {F{e_4}{{[Fe{{(CN)}_6}]}_3}}\limits_{{\rm{Prussion}}\,{\rm{blue}}} $.

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