MCQ
Pyramidal shape would be of
- A$NO_3^ - $
- B${H_2}O$
- ✓${H_3}{O^ + }$
- D$NH_4^ + $
$H _2 O$ has $sp ^3$ hybridisation $H _2 O$ is bent shaped molecule .
$H _3 O ^{+}$ has $sp ^3$ hybridisation and $H _3 O ^{+}$ is pyramidal
$NH _4^{+}$ has $sp ^3$ hybridisation and the shape of $NH _4^{+}$ is tetrahedral.
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${C_6}{H_6}\left( l \right) + \frac{{15}}{2}{O_2}\left( g \right) \longrightarrow 6C{O_2}\left( g \right) + 3{H_2}O\left( l \right)\,;\,\Delta H = - 3271\,kJ$
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