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4.2 friction — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics4.2 friction1 Mark
MCQ
Radius of the curved road on national highway is $R$. Width of the road is $b$. The outer edge of the road is raised by $h$ with respect to inner edge so that a car with velocity $v$ can pass safe over it. The value of $h$ is
  • ✓
    $\frac{{{v^2}b}}{{Rg}}$
  • B
    $\frac{v}{{Rgb}}$
  • C
    $\frac{{{v^2}R}}{g}$
  • D
    $\frac{{{v^2}b}}{R}$
✓

Answer

Correct option: A.
$\frac{{{v^2}b}}{{Rg}}$
a
(a) We know that $\tan \theta = \frac{{{v^2}}}{{Rg}}$ and $\tan \theta = \frac{h}{b}$

Hence $\frac{h}{b} = \frac{{{v^2}}}{{Rg}}$

$⇒$ $h = \frac{{{v^2}b}}{{Rg}}$

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