Range of the function 1 2 - 3x is - Vidyadip

MCQ

Range of the function $\frac{1}{{2 - \sin 3x}}$ is

A
$[1, 3]$
✓
$\left[ {\frac{1}{3},\,\,1} \right]$
C
$(1, 3)$
D
$\left( {\frac{1}{3},\;1} \right)$

✓

Answer

Correct option: B.

$\left[ {\frac{1}{3},\,\,1} \right]$

b
(b) $f(x) = \frac{1}{{2 - \sin 3x}},\,\,\sin 3x \in [ - 1,\,\,1]$

Hence $f(x)$ lies in $\left[ {\frac{1}{3},\,\,1} \right]$.

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