MCQ
Range of the function $f(x)=\frac{1}{3 x+2}$ is
  • A
    R
  • $R -\{0\}$
  • C
    $(0, \infty)$
  • D
    $R-\left\{-\frac{2}{3}\right\}$

Answer

Correct option: B.
$R -\{0\}$
(B)
$\operatorname{Dom}(f)=R-\left\{-\frac{2}{3}\right\}$
For Range(f), let $y= f (x)=\frac{1}{3 x+2}$
$\therefore \quad 3 x+2=\frac{1}{y} \Rightarrow x=\frac{1}{3}\left(\frac{1}{y}-2\right)$
$x$ is real if $y \neq 0$.
Hence, $R _{ f }= R -\{0\}$

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