- ✓$\frac{g}{2}$
- B$\frac{g}{5}$
- C$\frac{g}{10}$
- D$\frac{g}{12}$
$R=\frac{u^{2} \sin 2 \theta}{g}$
The time of flight of projectile motion is given as,
$T=\frac{2 u \sin \theta}{g}$
The square of time of flight of projectile motion is,
$T^{2}=\left(\frac{2 u \sin \theta}{g}\right)^{2}$
$=\frac{4 u^{2} \sin ^{2} \theta}{g^{2}}$
The ratio of maximum range and square of time of flight in projectile motion is calculated as,
$\frac{R}{T^{2}}=\frac{\frac{u^{2} \sin 2 \theta}{g}}{\frac{4 u^{2} \sin ^{2} \theta}{g^{2}}}$
$=\frac{g}{2} \cot \theta$
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Statement $II :$ If the road is banked at an angle of $45^{\circ}$, cyclist can cross the curve of $2\, m$ radius with the speed of $18.5\, kmh ^{-1}$ without slipping.
In the light of the above statements, choose the correct answer from the options given below.