MCQ
Reaction by which benzaldehyde cannot be prepared
- A(image) $+ CO + HCl$ in presence of anhydrous $AlCl_3$
- ✓(image)$+ Zn/Hg$ and conc. $HCl$
- C(image) $+ CrO_2Cl_2$ in $Cs_2$ followed by $H_3O^+$
- D(image) $+ H_2$ in presence of $Pd-BaSO_4$
✓
Answer
Correct option: B.
(image)$+ Zn/Hg$ and conc. $HCl$
b
In presence of $\mathrm{Zn}-\mathrm{Hg}$ and conc. $HCl$ reduction is useful specially for aldehyde and ketone but carboxylic group remains uneffected
In presence of $\mathrm{Zn}-\mathrm{Hg}$ and conc. $HCl$ reduction is useful specially for aldehyde and ketone but carboxylic group remains uneffected
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The calorific values of fats, carbohydrates and proteins vary in the order
Which of the following species is not paramagnetic ?
What is the order of reaction' for $A + B \to C$
→| Observation | $[A]$ | $[B]$ | Rate of reaction |
| $1$ | $0.1$ | $0.1$ | $2\times10^{-3}\, mol\, L^{-1}\,sec^{-1}$ |
| $2$ | $0.2$ | $0.1$ | $0.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$ |
| $3$ | $0.1$ | $0.2$ | $1.4\times10^{-2}\, mol\, L^{-1}\,sec^{-1}$ |
Most reactive compound towards grignard's reagent
Choose the incorrect option :
Which of the following is more basic than aniline?
An organic compound having the molecular formula $C_8H_{10}O$ on being heated with $I_2$ and dilute $NaOH$ gives a yellow precipitate. The expected compound is
→Number of chiral products (including stereoisomer).
Benzene reacts with chlorine in presence of light to yield:
For the reaction taking place on water, the order of reaction is
→${{H}_{2}}+C{{l}_{2}}\xrightarrow{\text{Sunlight}}2HCl$