MCQ
Reaction correctly matched with its name ?
- A(image) $+ CO + HCl =$ Sandmayer reaction

- B(image) $+ CuO_3 =$ Schotten Baumann reaction

- ✓(image) $\xrightarrow{{B{r_2} + KOH}} = $ Hoffmann Bromamide reaction

- DAll of these




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$CH _{3} CH = CHCH \left( CH _{3}\right)_{2} \stackrel{ HBr }{\longrightarrow}$
$(A)$ $P$ can be reduced to a primary alcohol using $NaBH _4$.
$(B)$ Treating $P$ with conc. $NH _4 OH$ solution followed by acidification gives $Q$.
$(C)$ Treating $Q$ with a solution of $NaNO _2$ in aq. $HCl$ liberates $N _2$.
$(D)$ $P$ is more acidic than $CH _3 CH _2 COOH$.