MCQ
Reaction of ammonia with excess $Cl _{2}$ gives :
- A$NH _{4} Cl$ and $N _{2}$
- B$NCl _{3}$ and $NH _{4} Cl$
- C$NH _{4} Cl$ and $HCl$
- ✓$NCl _{3}$ and $HCl$
✓
Answer
Correct option: D.
$NCl _{3}$ and $HCl$
d
$\begin{array}{*{20}{c}} {N{H_3} + 3C{l_2} \to NC{l_3} + 3HCl} \\ {excess\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}$
$\begin{array}{*{20}{c}} {N{H_3} + 3C{l_2} \to NC{l_3} + 3HCl} \\ {excess\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}$
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