MCQ
Reason for geometrical isomerism by $2-$butene is
- AChiral carbon
- BFree rotation about single bond
- CFree rotation about double bond
- ✓Restricted rotation about double bond
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$(i)$ $X + Y \rightleftharpoons M$ very rapid equilibrium
$(ii)$ $M + Z \to P$ slow
$(iii)$ $O + Y \to N$ very fast
What is the rate law for this reaction
Step $I\,\,:$ ${H_2}O(g)\, \to \,H(g)\, + \,OH(g)\,;$ $\Delta H = 498\,kJ\,mol^{-1}$
Step $II\,\,:$ $OH(g)\, \to \,H(g)\, + \,O(g)\,;$ $\Delta H = 428\,kJ\,mol^{-1}$
The bond enthalpy of the $O-H$ bond is....$kJ\,mol^{-1}$
$HC \equiv CH\mathop {\xrightarrow{{NaN{H_2},C{H_3}COC{H_3}}}}\limits_{{H^ + }} X\mathop {\xrightarrow{{H{g^{2 + }},{H_3}{O^ + }}}}\limits_{{H_2}O} Z$ is
